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The breakage in sha3 is expected breakage. A goal that was not solved by The fix is to prune the branch of the proof after the |
Co-authored-by: Copilot <copilot@github.com>
strub
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Jul 3, 2026
bgregoir
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Jul 3, 2026
| && EcReduction.EqTest.for_type env b1.e_ty b2.e_ty -> | ||
| List.fold_left2 (add_eqs_loc env local) eqs (b1::es1) (b2::es2) | ||
| | _, _ when EcReduction.EqTest.for_expr env e1 e2 -> | ||
| let fv1 = e_read env e1 in |
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I don't understand why you take the union.
Normally you should take the intersection.
The success of EqTest.for_expr should garantie
That the exists a term e such that e1 --> e and e2 --> e
So the free variable of e is in the intersection of e1 and e2.
If you take the union you may have variable bound in the first memory that will be unbound in the other.
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Fixes #990.
Maybe this should be fixed by making the equality check in pretty printing stronger instead. I'm not sure what's right here.
Blocked by #996.