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Binary Tree Level Order Traversal (Problem 1- Leetcode102.py)
Strengths:
Your solution correctly implements BFS for level order traversal
Good use of deque for O(1) popleft operations
The code is clean and follows Python conventions
You correctly handle the edge case of an empty tree
The algorithm matches the optimal approach
Areas for Improvement:
Remove commented-out code: The commented DFS approach should be removed for cleaner code. If you want to keep it as an alternative, put it in a separate function or commit.
Add type hints: Python supports type hints which would make the code more professional:
Consider edge case handling: While your solution handles root is None, you could also handle the case where the input might not be a TreeNode.
Variable naming: temp could be renamed to level or current_level for better readability.
VERDICT: PASS
Course Schedule (Problem 2- Leetcode207.py)
Great work! Your solution using Kahn's algorithm (BFS-based topological sort) is a clean and efficient alternative to DFS-based cycle detection. Here are some suggestions:
Fix the time complexity comment: Change #Time Complexity: O(n) to #Time Complexity: O(V + E) or #Time Complexity: O(numCourses + len(prerequisites)) to accurately reflect the algorithm's complexity.
Remove redundant check: The if not q: return False check is unnecessary because if the queue is empty, the while loop won't execute and the function will naturally return False at the end.
Consider using a defaultdict: Instead of checking if pr[1] not in graph, you could use from collections import defaultdict and graph = defaultdict(list) for cleaner code.
Good practices observed:
Proper use of deque for O(1) popleft operations
Early termination when all courses are processed
Clear variable naming and good code organization
VERDICT: PASS
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