BFS2-1 completed

[Keerthi0910]

No description provided.

[super30admin]

Rotting Oranges (Problem1.java)

Your solution is correct and well-implemented! Here are some observations:

Strengths:

1. Correct BFS implementation with proper level-by-level processing
2. Good handling of edge cases (no fresh oranges, no rotten oranges)
3. Clean, readable code with descriptive variable names
4. Proper use of Java collections (LinkedList for queue)
5. The early return when queue.size() == 0 is a nice touch

Minor improvements to consider:

1. Early exit optimization: You could add an early return inside the BFS loop when freshOrangesCount reaches 0, similar to the reference solution. This can save unnecessary iterations:

   if(freshOrangesCount == 0) return minutes;

2. Initial minutes value: Starting with minutes = -1 and incrementing at the start of each level is a clever way to handle the first iteration, but it can be confusing. An alternative is to start with minutes = 0 and increment after processing each level.
3. Use ArrayDeque: For better performance, consider using ArrayDeque instead of LinkedList for the queue, as ArrayDeque is generally faster for queue operations in Java.

Overall, this is a solid solution that demonstrates a good understanding of BFS and the problem requirements.

VERDICT: PASS

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Employee Importance (Problem2.java)

ESTIMATED GRADE: [A/B/C/D/F]

ESTIMATED GRADE: A

VERDICT: PASS