Binary-Search-1 problems

[paragc05]

No description provided.

[super30admin]

Search in Rotated Sorted Array (LC33_BS_rotated_sorted_array.py)

Excellent work! Your solution is correct, efficient, and well-documented. A few minor suggestions for future improvement:

1. Edge case consideration: While your solution handles all cases correctly, you could add a brief comment about edge cases (e.g., when the array isn't rotated, or when the array has only one element) to demonstrate deeper understanding.

2. Alternative approach: For learning purposes, you might also explore finding the pivot point first (using binary search to find the minimum element), then performing a standard binary search on the appropriate half. This is another common approach to this problem.

3. Testing: Consider adding test cases in your submission to verify correctness across various scenarios (rotated array, non-rotated array, target at boundaries, target not present).

Overall, this is a clean, professional solution that demonstrates strong understanding of binary search in rotated arrays.

VERDICT: PASS

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Search in a Sorted Array of Unknown Size (LC702_BS_sorted_array_of_unknown_size.py)

Excellent work! Your solution is a clean, correct implementation of the exponential search + binary search approach. The code is well-commented and follows Python best practices. The approach is optimal for this problem with O(log n) time complexity.

VERDICT: PASS

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Search a 2D Matrix (LC74_BS_2DMatrix.py)

Strengths:

• Correct implementation of the binary search approach
• Optimal time and space complexity
• Good comments explaining the approach
• Clean and readable code

Areas for improvement:

• Variable naming: Consider using rows and cols instead of m and n, or follow the convention where m represents rows and n represents columns. The current naming (m = len(matrix[0]) for columns and n = len(matrix) for rows) is unconventional and could be confusing.
• The comment "once we know what row the target exist we perform binary search" is slightly misleading. The solution performs a single binary search on the flattened array, not two separate binary searches. Consider revising this comment for clarity.
• Adding a brief explanation of why the division and modulo operations work (i.e., mid // m gives the row and mid % m gives the column) would be helpful for readers.

VERDICT: PASS