Completed Binary Search-1

[raninagare]

…array.

[super30admin]

Search in Rotated Sorted Array (SearchInRotatedSortedArray.java)

Excellent work! Your solution is correct, efficient, and well-implemented. Here are some specific points:

Strengths:

• Your implementation correctly identifies the sorted half in each iteration and makes the appropriate decision.
• The edge case handling for null/empty arrays is good practice.
• The code is clean, readable, and well-commented.
• The time and space complexity match the optimal solution.
• The header comment with complexity analysis is a great practice.

Minor suggestions for improvement:

• Consider adding more inline comments to explain the "why" behind certain decisions, not just the "what". For example, why does checking nums[left] <= nums[mid] indicate the left side is sorted?
• You could potentially combine the two else if conditions into a single else since they are mutually exclusive (if left is not sorted, then right must be sorted). However, the current approach is also fine for readability.
• Consider adding a brief explanation in the comments about why this approach works for rotated sorted arrays.

Overall, this is a high-quality solution that demonstrates a strong understanding of the binary search algorithm and its application to rotated sorted arrays.

VERDICT: PASS

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Search in a Sorted Array of Unknown Size (SerachInSortedArrayOfUnknownLength.java)

Your solution is correct and efficient! It matches the reference solution in both approach and complexity. Here are some minor suggestions:

1. Class naming: There's a typo in your class name - "Serach" should be "Search". While this doesn't affect functionality, it's good practice to use correct spelling for maintainability.

2. Comments: Your comments are helpful, but the time complexity comment "log (m+n)" is a bit confusing. It should be O(log n) where n is the size of the array.

3. Code style: Consider adding a space after if and else if keywords for better readability (e.g., if (reader.get(right) < target) instead of if(reader.get(right) < target)).

4. Edge cases: Your solution handles the edge cases well, but you might want to consider what happens if the array is empty or if the target is at the very beginning or end of the array.

Overall, this is a solid solution that demonstrates a good understanding of the problem and the algorithm.

VERDICT: PASS

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Search a 2D Matrix (SearchIn2DMatrix.java)

Strengths:

• Excellent solution that matches the optimal approach
• The header comment listing 5 different approaches shows deep understanding of the problem
• Clean, readable code with appropriate variable names
• Correct implementation of binary search with proper index conversion
• Good comments explaining the main idea

Areas for Improvement:

• The class name SearchIn2DMatrix should ideally be Solution to match LeetCode's expected format (though this depends on the platform)
• Consider adding a brief inline comment explaining why mid / n gives the row and mid % n gives the column, for educational purposes
• The header comment is comprehensive but could be more concise for production code

Overall, this is an excellent solution that demonstrates strong problem-solving skills.

VERDICT: PASS