Done Hashing-1

[ManasviReddy25]

No description provided.

[super30admin]

Grouping Anagrams Together (Problem1.py)

Strengths:

• Excellent documentation with time/space complexity analysis and LeetCode verification
• Clean, readable code with descriptive variable names
• Correct implementation of the prime-based hashing approach
• Proper use of defaultdict for cleaner code

Areas for Improvement:

• Avoid using map as a variable name since it shadows Python's built-in map() function. Consider using groups or anagram_map instead.
• The hash values can become very large for strings with many characters. Consider using a tuple of character counts as a dictionary key (more robust, though slightly slower).
• Could add type hints for better code documentation.

VERDICT: PASS

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Isomorphic Strings (Problem2.py)

Strengths:

• Correct algorithm implementation with proper bidirectional mapping checks
• Good use of descriptive variable names
• Clear comments explaining the logic
• Proper handling of edge cases (conflicts return false, new mappings recorded)

Areas for Improvement:

• Space complexity claim of O(1) is incorrect; dictionaries use O(k) space where k is the number of unique characters
• Comments are verbose; more concise inline comments would improve readability
• Consider using enumerate(s) instead of range(len(s)) for cleaner Python code
• Could add an early length check for better defensive programming

VERDICT: PASS

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Word Pattern (Problem3.py)

Strengths:

• Excellent implementation that matches the reference solution's approach
• Good use of descriptive variable names
• Clean code structure with proper indentation
• Well-documented with comments explaining the logic
• Proper handling of edge cases (length mismatch)

Areas for Improvement:

• The variable name str_ uses an underscore to avoid shadowing Python's built-in str type, which is good practice, but could also use a more descriptive name like s or input_string
• Consider combining the two mapping checks into a single condition for slightly more compact code:

  if pmap.get(pChar) != wChar or amap.get(wChar) != pChar:
      return False

• The comment "#check the index position of each char in pattern and array" could be more descriptive about what exactly is being checked

Overall, this is a solid solution that correctly solves the problem with good coding practices.

VERDICT: PASS