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36 changes: 36 additions & 0 deletions Problem 1- leetcode113.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,36 @@
#Time Complexity: O(n)
#Space Complexity: O(n) where n is the number of nodes in the tree

# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution(object):
def pathSum(self, root, targetSum):
"""
:type root: Optional[TreeNode]
:type targetSum: int
:rtype: List[List[int]]
"""
self.result = []
self.helper(root, targetSum, 0, [])
return self.result

def helper(self, root, targetSum, currSum, path):
if root is None:
return

currSum += root.val
path.append(root.val)

if root.left is None and root.right is None:
if currSum == targetSum:
self.result.append(list(path))

self.helper(root.left, targetSum, currSum, path)
self.helper(root.right, targetSum, currSum, path)

path.pop()

30 changes: 30 additions & 0 deletions Problem 2- Leetcode101.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,30 @@
#Time Complexity: O(n)
#Space Complexity: O(h) where h is the height of the tree

# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution(object):
def isSymmetric(self, root):
"""
:type root: Optional[TreeNode]
:rtype: bool
"""
return self.helper(root.left, root.right)

def helper(self, left, right):
if left is None and right is None:
return True

if left is None or right is None:
return False

if left.val != right.val:
return False

return (self.helper(left.left, right.right) and
self.helper(left.right, right.left))